g1: word = 10;
g2: byte = 20;
g3: {word, 100};
g4: {word, 1000};
g5: word = 40;

fn main()
    g1 = 11;
    g2 = 12;
    (g4@ + 200)^ = 14;
    %% 2048 - 12 - 4 == 2032
    (g4@ + 2032)^ = 15;
    (g4@ + 2036)^ = 16;
    g5 = 21;
end
